4x^2+60x=960

Solution for 4x^2+60x=960 equation:

4x^2+60x=960

We move all terms to the left:

4x^2+60x-(960)=0

a = 4; b = 60; c = -960;
Δ = b2-4ac
Δ = 602-4·4·(-960)
Δ = 18960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18960}=\sqrt{16*1185}=\sqrt{16}*\sqrt{1185}=4\sqrt{1185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{1185}}{2*4}=\frac{-60-4\sqrt{1185}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{1185}}{2*4}=\frac{-60+4\sqrt{1185}}{8}
$